Calculates the base 10 logarithm of a double field.
Note
Math functions on ARM architecture may return different results in very high-precision calculationsc compared to Intel/AMD architectures.
Hide omitted argument names for this function
Omitted Argument NamesThe argument name for
field
can be omitted; the following forms of this function are equivalent:logscale Syntaxmath:log10("value")
and:
logscale Syntaxmath:log10(field="value")
These examples show basic structure only.
math:log10()
Examples
Click
next to an example below to get the full details.Calculate Base 10 Logarithm of Values
Calculate the base 10 logarithm of a double field using the
math:log10()
function
Query
x := 100.0
| math:log10(x, as=log10_result)
Introduction
In this example, the math:log10()
function is used
to calculate the base 10 logarithm of a double-precision value, showing
how many times you need to multiply 10 by itself to get that value.
Step-by-Step
Starting with the source repository events.
- logscale
x := 100.0
Assigns the double-precision floating-point value
100.0
to a field named x. This value will be used to calculate its base 10 logarithm. Note the decimal point indicating a floating-point number. - logscale
| math:log10(x, as=log10_result)
Calculates the base 10 logarithm of the double-precision value in field x and returns the result in a new field named log10_result as a double-precision number. If the
as
parameter is not specified, the result is returned in a field named _log10 as default. Event Result set.
Summary and Results
The query is used to calculate the base 10 logarithm of a double-precision value, which is useful in analyzing exponential growth or decay in decimal systems.
This query is useful, for example, to analyze orders of magnitude in scientific notation, convert between linear and logarithmic scales, or measure exponential relationships in scientific applications where precise floating-point calculations are required.
Sample output from the incoming example data:
log10_result |
---|
2.000000 |
The result shows that the base 10 logarithm of 100.0 =
2.000000
, meaning that
10² = 100
. This indicates
that you need to multiply 10 by itself 2 times to get 100.
Some other examples with double-precision values:
base 10 logarithm of 10.0 = 1.000000 (
10¹ = 10
)base 10 logarithm of 1000.0 = 3.000000 (
10³ = 1000
)base 10 logarithm of 1.0 = 0.000000 (
10⁰ = 1
)base 10 logarithm of 0.1 = -1.000000 (
10⁻¹ = 0.1
)